(r-20)^(1/2)=r

Solution for (r-20)^(1/2)=r equation:

(r-20)^(1/2)=r

We move all terms to the left:

(r-20)^(1/2)-(r)=0

We add all the numbers together, and all the variables

(r-20)^(+1/2)-r=0

We add all the numbers together, and all the variables

-1r+(r-20)^(+1/2)=0

We multiply all the terms by the denominator


-1r*2)+(r+1-20)^(=0

We add all the numbers together, and all the variables

-1r*2)+(r-19)^(=0

We add all the numbers together, and all the variables

-1r*2)+(r=0

Wy multiply elements

-2r^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-4}=0$